1/9x^2-5x+27=0

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Solution for 1/9x^2-5x+27=0 equation: 



1/9x^2-5x+27=0



Domain of the equation: 9x^2!=0

x^2!=0/9

x^2!=√0

x!=0

x∈R



We add all the numbers together, and all the variables

-5x+1/9x^2+27=0

We multiply all the terms by the denominator


-5x*9x^2+27*9x^2+1=0

Wy multiply elements

-45x^3+243x^2+1=0

We do not support expression: x^3

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